Homework 2 - Solutions
1. Using the notation suggested in the following diagram, answer the following questions:

a. Find all of the equivalent descriptions of the mapping

and the mapping

(4 pts.)

(Notice that these each rotations of

degrees in the counter clockwise direction.)

(Notice that these are all half turns.)
b. What is the smallest group containing the reflection

?
Be sure your list only contains one description of each mapping. (4 pts.)
The smallest group (or least of mappings generated by

is

Here is the multiplication table:
![]() ![]() |
![]() ![]() |
|
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
c.. What is the smallest group containing the mappings

and

?
Be sure your list only contains one description of each mapping.(4 pts.)
Recall that

and hence

and that

It follows that smallest group (or least of mappings generated by

and

is

Here is the multiplication table:
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
|
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
d. What is the smallest group containing

and

Be sure your list only contains one description of each mapping.(8
pts.)
This turns out to be all of the symmetries!. The list is

Here is the multiplication table:
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
|
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
![]() ![]() |
2. Using your MIRA, carefully plot the path a ball would follow in order to achieve a hole in one. Prove that your path is the shortest path the ball could take to the hole. (6 pts.)

In order to show that

is shortest possible (two bank path using the bottom and right hand rails)
from

to

one can argue by selecting two points

and

with either

or

and then showing that

To argue this, let

be the reflection of

over the bottom rail and

be the reflection over right hand rail. Note that

and

are, respectively, the interesections of

with the bottom rail and the right hand rail. Now, as reflections are being
assumed to preserve distance, two applications of the triangle inequality
yield that:

As
either

or

,
one of the above inequalities must be strict and hence
