Notes for Homework #3
The definition of similar triangles follows the same format as the definition
of congruent triangles. One first defines what it means for a correspondence
between the vertices of the triangles to be a `similarity' and then defines
two triangles to be similar if there is a similarity between their
vertices.
Definition: Let

and

be
two triangles. The correspondence

is
a similarity provided that corresponding angles are congruent and

In
the event the correspondence

is
a similarity, we write

and
say that the triangles

and

are
similar.
Recall that when establishing two triangles are congruent one does not need to
establish that every pair of corresponding angles are congruent and every pair
of corresponding sides are congruent. The



and

criteria for congruence tells us that we just need to test some of the pairs
in order to conclude that the two triangles are congruent. The situation is
similar for similar triangles. Just as in the case for the congruence of
triangles, it turns out that in order show that

is similar to

one does not need to establish that every pair of corresponding angles are
congruent and that every pair of corresponding sides are proportional. In
particular, one can establish the following:
Theorem: Let

and

be
two triangles. Then:
1. AAA criteria: If the corresponding angles are congruent, then

is
similar to

2. SSS criteria: If

then

is
similar to

3.SAS criteria: If

is
congruent to

and

then

is
similar to

During the lecture we also gave a definition of the sine and cosine of an
angle. Just for completeness sake, it is included here. It may be useful in
problem 2.
Definition: Given

,
define

and

as
follows:
1. If

is
acute, form a right triangle

with
right angle at

.
Then

2. If

is
a right angle, let

and
cos


3. If

is
obtuse and

is
a supplement of

,
then let

and
cos


Name:______________________________
Math 330B - Homework 3
Problem 1: Using the SAS criteria for similarity (see the
first page), prove the `midsegment theorem': Let

be a triangle and suppose that

is the midpoint of

and

is the midpoint of

Prove that

is parallel to

and

(8 pts.)

Problem
2 :Prove the Law of Sines: If

is any triangle, then

In order to prove this, let

be the foot of the perpendicular dropped from

to

.
The key to the proof is to use compute

using

and

,
compute

using

and

,
set the results equal to one another, and then simplify. Notice that there are
a number of cases that need to be considered:




and

.
a. Prove the result when

Include a diagram that illustrates this case. (4
pts.)
b. Prove the result when

Include a diagram that illustrates this case.(4 pts.)